lim (2x^2 + 3x - 2)/(x^2 - 4) x tiến đến -2 bằng

Chọn A

Ta có $\underset{\mathrm{x}\to -2}{\lim }\frac{2{\mathrm{x}}^2+3\mathrm{x}-2}{{\mathrm{x}}^2-4}$$=\underset{\mathrm{x}\to -2}{\lim }\frac{\left(2\mathrm{x}-1\right)\left(\mathrm{x}+2\right)}{\left(\mathrm{x}-2\right)\left(\mathrm{x}+2\right)}$$=\underset{\mathrm{x}\to -2}{\lim }\frac{2\mathrm{x}-1}{\mathrm{x}-2}=\frac{5}{4}$.