Nếu \(\mathop {\lim }\limits_{x \to 1} \frac{{f\left( x \right) - 5}}{{x - 1}} = 2\); \(\mathop {\lim }\limits_{x \to 1} \frac{{g\left( x \right) - 1}}{{x - 1}} = 3\) thì \(\mathop...

Câu hỏi :

Nếu \(\mathop {\lim }\limits_{x \to 1} \frac{{f\left( x \right) - 5}}{{x - 1}} = 2\) và \(\mathop {\lim }\limits_{x \to 1} \frac{{g\left( x \right) - 1}}{{x - 1}} = 3\) thì \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {f\left( x \right).g\left( x \right) + 4}  - 3}}{{x - 1}}\) bằng