\(\mathop {\lim }\limits_{x \to 0} \frac{{x.\sin 2x}}{{1 - \cos 3x}}\) bằng:

Câu hỏi :

\(\mathop {\lim }\limits_{x \to 0} \frac{{x.\sin 2x}}{{1 - \cos 3x}}\) bằng:

A. \(\frac{3}{5}\)

B. \( - \frac{3}{5}\)

C. \(\frac{4}{9}\)

D. \(-\frac{5}{3}\)

* Đáp án

C

Copyright © 2021 HOCTAP247