Tìm giới hạn \(\mathop {\lim }\limits_{x \to 0} \dfrac{{\sqrt {(2x + 1)(3x + 1)(4x + 1)} - 1}}{x}\)

* Hướng dẫn giải

\(\begin{array}{l}\mathop {\lim }\limits_{x \to 0} \dfrac{{\sqrt {(2x + 1)(3x + 1)(4x + 1)}  - 1}}{x}\\ = \mathop {\lim }\limits_{x \to 0} \dfrac{{(2x + 1)(3x + 1)(4x + 1) - 1}}{{x.(\sqrt {(2x + 1)(3x + 1)(4x + 1)}  + 1)}}\\ = \mathop {\lim }\limits_{x \to 0} \dfrac{{24{x^3} + 26{x^2} + 9x}}{{x.(\sqrt {(2x + 1)(3x + 1)(4x + 1)}  + 1)}}\\ = \mathop {\lim }\limits_{x \to 0} \dfrac{{24{x^2} + 26x + 9}}{{(\sqrt {(2x + 1)(3x + 1)(4x + 1)}  + 1)}} = \dfrac{9}{2}\end{array}\)