lim x->1 (2x^3 - 3x + 1)/(2 - 2x^2) bằng: 1/2; 1/4; -1/4

* Hướng dẫn giải

Chọn C

$\underset{x\to 1}{\lim }\frac{2x^3-3x+1}{2-2x^2}=\underset{x\to 1}{\lim }\frac{\left(x-1\right)\left(2x^2+2x-1\right)}{-2\left(x-1\right)\left(x+1\right)}=\underset{x\to 1}{\lim }\frac{2x^2+2x-1}{-2\left(x+1\right)}=-\frac{3}{4}$