Tích phân \(\int\limits_0^2 {\left( {{x^2} - 2x + 3} \right)dx} \) bằng

* Hướng dẫn giải

\(\int\limits_0^2 {\left( {{x^2} - 2x + 3} \right){\rm{d}}x}  = \left. {\frac{{{x^3}}}{3}} \right|_0^2 - \left. {{x^2}} \right|_0^2 + \left. {3x} \right|_0^2 = \frac{8}{3} - 4 + 6 = \frac{{14}}{3}.\)