Nếu \(\int\limits_1^3 {f(x)dx} = 8\) thì \(\int\limits_1^3 {\left[ {\frac{1}{2}f\left( x \right) + 1} \right]dx} \) bằng

* Hướng dẫn giải

\(\int\limits_1^3 {\left[ {\frac{1}{2}f\left( x \right) + 1} \right]dx}  = \frac{1}{2}\int\limits_1^3 {f\left( x \right)dx}  + \int\limits_1^3 {dx}  = \frac{1}{2}.8 + 2 = 6\)