Trong không gian với hệ tọa độ Oxyz, cho đường thẳng d: (x + 2)/2 = y/-1 = (z + 1)/2

A. ${\mathrm{d}}_1:\left\{\begin{array}{c}\mathrm{x}=2+3\mathrm{t}\\ \mathrm{y}=2-\mathrm{t}\\ \mathrm{z}=1+4\mathrm{t}\end{array}\right.$

B. ${\mathrm{d}}_2:\left\{\begin{array}{c}\mathrm{x}=3\mathrm{t}\\ \mathrm{y}=1+\mathrm{t}\\ \mathrm{z}=5\mathrm{t}\end{array}\right.$

C. ${\mathrm{d}}_3:\frac{\mathrm{x}+2}{-4}=\frac{\mathrm{y}+3}{2}=\frac{\mathrm{z}-1}{-4}$

D. ${\mathrm{d}}_4:\frac{\mathrm{x}}{6}=\frac{\mathrm{y}+1}{-3}=\frac{\mathrm{z}-1}{6}$