Cho hai đường thẳng delta, delta' có VTCP lần lượt là vecto u, vecto u'

A. $\mathrm{d}\left(\mathrm{\Delta },\mathrm{\Delta }\text{'}\right)=\frac{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{u}\text{'}}\right].\overrightarrow{\mathrm{MM}\text{'}}\right|}{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{u}\text{'}}\right]\right|}$

B. $\mathrm{d}\left(\mathrm{\Delta },\mathrm{\Delta }\text{'}\right)=\frac{\left|\left[\overrightarrow{\mathrm{MM}\text{'}},\overrightarrow{\mathrm{u}\text{'}}\right].\overrightarrow{\mathrm{u}}\right|}{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{u}\text{'}}\right]\right|}$

C. $\mathrm{d}\left(\mathrm{\Delta },\mathrm{\Delta }\text{'}\right)=\frac{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{u}\text{'}}\right].\overrightarrow{\mathrm{MM}\text{'}}\right|}{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{MM}\text{'}}\right]\right|}$

D. $\mathrm{d}\left(\mathrm{\Delta },\mathrm{\Delta }\text{'}\right)=\frac{\left|\left[\overrightarrow{\mathrm{u}},\overrightarrow{\mathrm{u}\text{'}}\right].\overrightarrow{\mathrm{MM}\text{'}}\right|}{\left|\overrightarrow{\mathrm{MM}\text{'}}\right|}$