Trắc nghiệm Toán 12 Chương 2 Bài 3 Lôgarit

A. \(P = \frac{3}{{10}}\)

B. \(P = 4\)​

C. \(P = \frac{1}{2}\)​

D. \(P = \frac{1}{4}\)​

A. \({\log _6}45 = \frac{{2{a^2} - 2ab}}{{ab}}\)

B. \({\log _6}45 = \frac{{2{a^2} - 2ab}}{{ab + b}}\)

C. \({\log _6}45 = \frac{{a + 2ab}}{{ab + b}}\)

D. \({\log _6}45 = \frac{{a + 2ab}}{{2ab + b}}\)

A. \({\log _2}3 = \frac{{1 - a}}{{a - 2}}\)

B. \({\log _2}3 = \frac{{2a - 1}}{{a - 2}}\)

C. \({\log _2}3 = \frac{{a - 1}}{{2a - 2}}\)

D. \({\log _2}3 = \frac{{1 - 2a}}{{a - 2}}\)

A. \(3\log (a + b) = \frac{1}{2}({\log _a} + {\log _b})\)

B. \(\log \frac{{a + b}}{3} = \frac{1}{2}({\log _a} + {\log _b})\)

C. \(2({\log _a} + {\log _b}) = \log (7ab)\)

D. \(2({\log _a} + {\log _b}) = \log (7ab)\)

A. \(P = 1 + \frac{{ab}}{{a + b}}\)

B. \(P = \frac{{2 + b + ab}}{{1 + b}}\)

C. \(P = 1 + \frac{{ab}}{{1 + b}}\)

D. \(P = \frac{{2 + a + ab}}{{1 + a}}\)

A. 1

B. \(\log \frac{x}{y}\)

C. \(\frac{{\log y}}{x}\)

D. \(\log \frac{{{a^2}y}}{{{d^2}x}}\)

A. 1

B. log₇10

C. 7

D. log7

A. -3

B. -2

C. 2

D. 3

A. 5log3

B. 3-3log2

C. 100log1,25

D. (log25)(log5)