A. \(m = \pm \sqrt 6 \)
B. \(m = \pm 2\sqrt 5 \)
C. \(m = \pm 2\sqrt 2 \)
D. \(m = \pm 3\sqrt 2 \)
A. D(-2;2;5)
B. D(-2;8;-3)
C. D(-4;8;-5)
D. D(-4;8;-3)
A.
H(3; 0; 2)
B. H (2; 0; 3)
C. H (2; 0; 3)
D. H (3; 2; 0)
A. \(I\left( {3;2;4} \right),R = 25\)
B. \(I\left( {-3;2;-4} \right),R = 25\)
C. \(I\left( {-3;2;-4} \right),R = 5\)
D. \(I\left( {3;-2;4} \right),R = 5\)
A. \(x-2y+3z-1=0\)
B. \(x-2y+3z+3=0\)
C. \(x-2y+3z-3=0\)
D. \(x-2y+3z+1=0\)
A. \({\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z - 1} \right)^2} = 3\)
B. \({\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z - 1} \right)^2} = 9\)
C. \({\left( {x - 1} \right)^2} + {\left( {y - 3} \right)^2} + {\left( {z - 1} \right)^2} = 36\)
D. \({\left( {x + 1} \right)^2} + {\left( {y + 3} \right)^2} + {\left( {z + 1} \right)^2} = 9\)
A. \(I\left( {1; - 2;0} \right),R = \sqrt 5 \)
B. \(I\left( {-1; 2;0} \right),R = \sqrt 5 \)
C. \(I\left( {-1; - 2;0} \right),R = 5 \)
D. \(I\left( {1; - 2;0} \right),R = 5 \)
A.
N(0 ;3 ;0)
B. N(0 ;3 ;0)
C. Q(6 ;0 ;0)
D. M(0;0;2)
A. \(x-2y-2z=0\)
B. \(x+2y+2z=0\)
C. \(x+6y+11z=0\)
D. \(x+2y+z=0\)
A. \(\overrightarrow {AB} = \left( {1; - 11} \right)\)
B. \(\overrightarrow {AB} = \left( {3; - 3;3} \right)\)
C. \(\overrightarrow {AB} = \left( {3; - 3; - 3} \right)\)
D. \(\overrightarrow {AB} = \left( {1;1; - 3} \right)\)
A.
(P): 2x – y – z – 2 = 0
B. (P): x – 2y – 2z + 2 = 0
C. (P): 2x + y + z – 6 = 0
D.
(P): x + 2y + 2z – 6 = 0
A. \(AM = 2\sqrt 7 \)
B. \(AM = \sqrt {30} \)
C. \(AM = \sqrt 5 \)
D. \(AM = 3\sqrt 3 \)
A. \(\cos \alpha = \frac{{\sqrt 3 }}{3}\)
B. \(\cos \alpha = \frac{1}{{14}}\)
C. \(\cos \alpha = \frac{1}{{7}}\)
D. \(\cos \alpha = \frac{1}{{\sqrt {14} }}\)
A. M(0;3;0)
B. N(6 ;3 ;2)
C. P(6 ;0 ;0 )
D. Q(0 ;0 ;2)
A. \(\overrightarrow n = \left( {0; - 3; - 1} \right)\)
B. \(\overrightarrow n = \left( {0; 3; 1} \right)\)
C. \(\overrightarrow n = \left( {0; - 3; 1} \right)\)
D. \(\overrightarrow n = \left( {2; - 3; 1} \right)\)
A. y - z = 0
B. x = 0
C. y = 0
D. z = 0
Lời giải có ở chi tiết câu hỏi nhé! (click chuột vào câu hỏi).
Copyright © 2021 HOCTAP247