Cho \(\int_0^3 {\left( {x - 1} \right){3^{{x^2} - 2x}}dx = \frac{a}{{\ln b}}} ,\,\,\left( {a,b \in N*} \right)\). Tính S = a - b

Câu hỏi :

Cho \(\int_0^3 {\left( {x - 1} \right){3^{{x^2} - 2x}}dx = \frac{a}{{\ln b}}} ,\,\,\left( {a,b \in N*} \right)\). Tính S = a - b