Cho hai đường thẳng: \({d_1}:\frac{{x + 7}}{4} = \frac{y}{1} = \frac{{z - 1}}{1}\) và \({d_2}:\frac{{x - 2}}{3} = \frac{{y - 1}}{{ -

A. \(d:\left\{ \begin{array}{l}
x = 1 + 2t\\
y = 2 - t\\
z =  - 3 - 7t
\end{array} \right.\)

B. \(d:\left\{ \begin{array}{l}
x = 1 + 2t\\
y = 2 + t\\
z =  - 3 - 7t
\end{array} \right.\)

C. \(d:\left\{ \begin{array}{l}
x = 1 + 3t\\
y = 2 - t\\
z =  - 3 + t
\end{array} \right.\)

D. \(d:\left\{ \begin{array}{l}
x = 1 + 4t\\
y = 2 + t\\
z =  - 3 + t
\end{array} \right.\)