Cho \(f\left( x \right) = \frac{{{x^2}}}{{ - x + 1}}\). Tính \({f^{\left( {2018} \right)}}\left( x \right)\)

A. \( - \frac{{2018!}}{{{{\left( { - x + 1} \right)}^{2018}}}}\)

B. \(\frac{{2018!}}{{{{\left( { - x + 1} \right)}^{2019}}}}\)

C. \( - \frac{{2018!}}{{{{\left( { - x + 1} \right)}^{2019}}}}\)

D. \(\frac{{2018!}}{{{{\left( { - x + 1} \right)}^{2018}}}}\)