Tính tích phân sau: ( 2 cosx − sin 2x ) dx

* Hướng dẫn giải

Chọn C

$$\begin{gathered} {\int }_0^{\frac{\mathrm{\pi }}{2}}\left(2\cos x-\sin 2x\right)dx \\ =2{\int }_0^{\frac{\mathrm{\pi }}{2}}\cos xdx-{\int }_0^{\frac{\mathrm{\pi }}{2}}\sin 2xdx \\ =2\sin x\overline{)\begin{array}{c}\frac{\mathrm{\pi }}{2}\\ 0\end{array}+\frac{1}{2}\cos 2x\overline{)\begin{array}{c}\frac{\mathrm{\pi }}{2}\\ 0\end{array}=1}} \end{gathered}$$