Cho \(\int\limits_0^2 {f\left( x \right)dx = - 3} ,\) \(\int\limits_0^5 {f\left( x \right)dx = 7} \). Khi đó \(\int\limits_2^5 {f\left( x \right)dx} \) bằng:

* Hướng dẫn giải

Ta có

\(\begin{array}{l}\int\limits_0^2 {f\left( x \right)dx}  + \int\limits_2^5 {f\left( x \right)dx}  = \int\limits_0^5 {f\left( x \right)dx} \\ \Rightarrow  - 3 + \int\limits_2^5 {f\left( x \right)dx}  = 7\\ \Leftrightarrow \int\limits_2^5 {f\left( x \right)dx}  = 7 - \left( { - 3} \right) = 10.\end{array}\)