Cho \(\int\limits_{0}^{2}{f\left( x \right)\text{d}x}=3,\int\limits_{0}^{2}{g\left( x \right)\text{d}x}=-1\) thì \(\int\limits_{0}^{2}{\left[ f\left( x \right)-5g\left( x \right)+x...

* Hướng dẫn giải

\(\int\limits_0^2 {\left[ {f\left( x \right) - 5g\left( x \right) + x} \right]{\rm{d}}x} = \int\limits_0^2 {f\left( x \right)dx - 5\int\limits_0^2 {{\rm{g}}\left( x \right){\rm{d}}x + \int\limits_0^2 {x{\rm{d}}x} } } = 3 + 5 + 2 = 10\)