Rút gọn \(P=\frac{{{a}^{\sqrt{3}+1}}.{{a}^{2-\sqrt{3}}}}{{{\left( {{a}^{\sqrt{2}-2}} \right)}^{\sqrt{2}+2}}}.\)

* Hướng dẫn giải

Ta có: \(P=\frac{{{a}^{\sqrt{3}+1+2-\sqrt{3}}}}{{{a}^{\left( \sqrt{2}-2 \right)\left( \sqrt{2}+2 \right)}}}=\frac{{{a}^{3}}}{{{a}^{-2}}}={{a}^{5}}.\)