A. \(\left\{ \begin{array}{l} x = - 2 + 3t\\ y = - 2 - 2t \end{array} \right.\)
B. \(\left\{ \begin{array}{l} x = - 2 - 4t\\ y = 1 - 3t \end{array} \right.\)
C. \(\left\{ \begin{array}{l} x = - 2 - 3t\\ y = 1 - 4t \end{array} \right.\)
D. \(\left\{ \begin{array}{l} x = - 2 - 3t\\ y = 1 + 4t \end{array} \right.\)
B
\(\left\{ \begin{array}{l} A\left( { - 2;1} \right) \in AB,\,\,\,{{\vec u}_{CD}} = \left( {4;3} \right)\\ AB||CD \to {{\vec u}_{AB}} = - {{\vec u}_{CD}} = \left( { - 4; - 3} \right) \end{array} \right.\\ \Rightarrow AB:\left\{ \begin{array}{l} x = - 2 - 4t\\ y = 1 - 3t \end{array} \right.\left( {t \in R} \right).\)
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