Hàm số \(y = \left| {x + 1} \right| + \left| {x - 3} \right|\) được viết lại là

Câu hỏi :

Hàm số \(y = \left| {x + 1} \right| + \left| {x - 3} \right|\) được viết lại là

A. \(y = \left\{ \begin{array}{l}
 - 2x + 2\,\,\,\,khi\,\,\,\,x \le  - 1\\
4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\,\, - 1 < x \le 3\\
2x - 1\,\,\,\,\,\,\,khi\,\,\,\,x > 3
\end{array} \right.\)

B. \(y = \left\{ \begin{array}{l}
2x - 2\,\,\,\,\,\,\,khi\,\,\,\,x \le  - 1\\
4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\, - 1 < x \le 3\\
 - 2x + 2\,\,\,khi\,\,\,x > 3
\end{array} \right.\)

C. \(y = \left\{ \begin{array}{l}
2x + 2\,\,\,\,\,\,\,\,khi\,\,\,\,x \le  - 1\\
4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\, - 1 < x \le 3\\
 - 2x - 2\,\,\,\,khi\,\,\,\,\,x > 3
\end{array} \right.\)

D. \(y = \left\{ \begin{array}{l}
 - 2x + 2\,\,\,\,khi\,\,\,x \le  - 1\\
4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\,\, - 1 < x \le 3\\
2x - 2\,\,\,\,\,\,khi\,\,\,\,x > 3
\end{array} \right.\)

* Đáp án

D

* Hướng dẫn giải

\(y = \left| {x + 1} \right| + \left| {x - 3} \right| = \left\{ \begin{array}{l}
 - x - 1 - x + 3\,\,\,khi\,\,\,x \le  - 1\\
x + 1 - x + 3\,\,\,\,\,\,khi\,\,\,\, - 1 < x \le 3\\
x + 1 + x - 3\,\,\,\,\,\,khi\,\,\,\,x > 3
\end{array} \right. = \left\{ \begin{array}{l}
 - 2x + 2\,\,\,khi\,\,\,x \le  - 1\\
4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\,\, - 1 < x \le 3\\
2x - 2\,\,\,\,\,\,khi\,\,\,\,x > 3
\end{array} \right.\)

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