Cho phương trình \(2{x^2} - x = 0\) (1).

* Hướng dẫn giải

Ta có 

\(\begin{array}{l}
2x - \frac{x}{{1 - x}} = 0 \Rightarrow 2{x^2} - x = 0\\
4{x^3} - x = 0 \Leftrightarrow \left[ \begin{array}{l}
x = 0\\
4{x^2} - 1 = 0
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = 0\\
x = \frac{1}{2}\\
x =  - \frac{1}{2}
\end{array} \right.\\
{\left( {2{x^2} - x} \right)^2} = 0 \Leftrightarrow 2{x^2} - x = 0 \Leftrightarrow \left[ \begin{array}{l}
x = 0\\
x = \frac{1}{2}
\end{array} \right.\\
{x^2} - 2x + 1 = 0 \Leftrightarrow x = 1
\end{array}\)