Nếu \(5\sin \alpha  = 3\sin \left( {\alpha  + 2\beta } \right)\) thì

Câu hỏi :

Nếu \(5\sin \alpha  = 3\sin \left( {\alpha  + 2\beta } \right)\) thì:

A. \(\tan \left( {\alpha  + \beta } \right) = 5\tan \beta .\)

B. \(\tan \left( {\alpha  + \beta } \right) = 4\tan \beta .\)

C. \(\tan \left( {\alpha  + \beta } \right) = 2\tan \beta .\)

D. \(\tan \left( {\alpha  + \beta } \right) = 3\tan \beta .\)

* Đáp án

B

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