Este X hai chức mạch hở, tạo bởi

* Hướng dẫn giải

Chọn đáp án C

$\begin{array}{l}\left\{\begin{array}{l}X:C_n{H}_{2n-2}{O}_4\text{ a}\\ Y:C_m{H}_{2m-10}{O}_6\text{ b}\end{array}\right.\left|\begin{array}{l}m\left(gam\right)\stackrel{+O_2\text{ 0,5}}{\to }\left\{\begin{array}{l}C{O}_2\text{ 0,45}\\ {\text{H}}_{2}O\end{array}\right.\\ \mathrm{0,16}\text{ (mol) }\stackrel{+NaOH\text{ 0,42}}{\to }3\text{ muoi + 2 ancol cung C}\end{array}\right.\\ Sau\text{ phan ung thu duoc 2 ancol cung C}\stackrel{}{\to }\left\{\begin{array}{l}{C}_3{H}_5{\left(OH\right)}_3\\ C_3{H}_6{\left(OH\right)}_2\end{array}\right.\end{array}$

$\left\{\begin{array}{l}BTE:\mathrm{0,45.6}-10a-22b=\mathrm{0,5.4}\\ \frac{n_E}{n_{COO}}=\frac{a+b}{2a+3b}=\frac{\mathrm{0,16}}{\mathrm{0,42}}\end{array}\right.\stackrel{}{\to }\left\{\begin{array}{l}a=\mathrm{0,015}\\ b=\mathrm{0,025}\end{array}\right.$

$\begin{array}{l}Chay\text{ C: 0,015n + 0,025m = 0,45}\stackrel{}{\to }\left\{\begin{array}{l}3n+5m=90\\ n>5;m\ge 12\end{array}\right.\stackrel{}{\to }\left\{\begin{array}{l}n=10\\ m=12{\text{ (C}}_2{H}_{3}COO{)}_3{C}_3{H}_5\end{array}\right.\\ \text{0,16 mol E}\left\{\begin{array}{l}{C}_{10}{H}_{18}{O}_4\text{ 0,06}\\ {\text{C}}_{12}{H}_{14}{O}_6\text{ 0,1}\end{array}\right.\stackrel{+NaOH\text{ 0,42}}{\to }\left\{\begin{array}{l}RCOONa\\ C_2{H}_{3}COONa\text{ 0,3}\end{array}\right.+\left\{\begin{array}{l}{C}_3{H}_6{\left(OH\right)}_2\text{ 0,06}\\ {\text{C}}_3{H}_5{\left(OH\right)}_3\text{ 0,1}\end{array}\right.\\ BTKL:m_{muoi}=a=(\mathrm{0,06.202}+\mathrm{0,1.254}+\mathrm{0,42.40})-(\mathrm{0,06.76}+\mathrm{0,1.92})=\mathrm{40,56}g\\ \%m_{C_2{H}_{3}COONa}=\frac{\mathrm{0,3.94}}{\mathrm{40,56}}.100=\mathrm{69,53}\%\end{array}$