Hỗn hợp X gồm 2 triglixerit A và B (MA

Chọn đáp án D

Ta có: $n_{B{r}_2}=\mathrm{0,825}\stackrel{}{\to }\left\{\begin{array}{l}C{O}_2:\mathrm{16,35}\\ H_{2}O:\mathrm{14,925}\end{array}\right.$ Xem như hidro hóa X rồi đốt cháy

$\begin{array}{l}\stackrel{}{\to }\mathrm{16,35}-\left(\mathrm{14,925}+\mathrm{0,825}\right)=2n_X\stackrel{}{\to }{n}_X=\mathrm{0,3}\stackrel{}{\to }\left\{\begin{array}{l}{n}_A=\mathrm{0,1125}\\ n_B=\mathrm{0,1875}\end{array}\right.\\ \stackrel{}{\to }\left\{\begin{array}{l}{C}_{15}{H}_{31}COONa:a\\ C_{17}{H}_{35}COONa:b\\ C_{17}{H}_{31}COONa:c\end{array}\right.\stackrel{}{\to }\left\{\begin{array}{l}a+b+c=\mathrm{0,9}\\ 2c=\mathrm{0,825}\\ 16a+18b+18c=\mathrm{16,35}-\mathrm{0,3.3}\end{array}\right.\stackrel{}{\to }\left\{\begin{array}{l}a=\mathrm{0,375}\\ b=\mathrm{0,1125}\\ c=\mathrm{0,4125}\end{array}\right.\\ \stackrel{}{\to }y+z=\mathrm{228,825}\left(gam\right)\end{array}$