X là hỗn hợp chứa một axit đơn chức

Chọn đáp án C

Giải thích:

$Ancolno,haichuc,co3Cla{C}_3{H}_6{\left(OH\right)}_2$

$\left\{\begin{array}{l}Axitno,donchuc:\underset{1\pi }{\underbrace{C_n{H}_{2n}{O}_2}}\stackrel{caét}{\to }\underset{1\pi }{\underbrace{COO}}+\underset{0\pi }{\underbrace{C_{n\text{'}}{H}_{2n\text{'}+2}}}\stackrel{caét}{\to }COO+C{H}_2+H_2\Rightarrow n_{H_2}=n_{axit}\\ Ancolno:C_3{H}_6{\left(OH\right)}_2\iff C_3{H}_8{O}_2\stackrel{cat}{\to }{C}_3{H}_6+H_2{O}_2\stackrel{cat}{\to }C{H}_2+H_2{O}_2\Rightarrow n_{H_2{O}_2}=n_{ancol}\\ Esteno,haichuc:\underset{2\pi }{\underbrace{C_m{H}_{2m-4}{O}_4}}\stackrel{cat}{\to }\underset{2\pi }{\underbrace{2COO}}\stackrel{cat}{\to }\underset{0\pi }{\underbrace{C_{m\text{'}}{H}_{2m\text{'}+2}}}\stackrel{cat}{\to }COO+C{H}_2+H_2\Rightarrow n_{H_2}=n_{este}\end{array}\right.$

$\Rightarrow X\stackrel{cat}{\to }\left\{\begin{array}{l}COO:\mathrm{0,1}mol(=n_{KOH})\\ C{H}_2:xmol\\ (H_2,H_2{O}_2):\mathrm{0,09}mol(=n_X)\end{array}\right\}\stackrel{\mathrm{0,48}mol{O}_2}{\to }\left\{\begin{array}{l}C{O}_2:(\mathrm{0,1}+x)mol\\ H_{2}O:(\mathrm{0,09}+x)mol\end{array}\right\}$

$\begin{array}{l}\Rightarrow 44(\mathrm{0,1}+x)-18(\mathrm{0,09}+x)=\mathrm{10,84}\Rightarrow x=\mathrm{0,31}\Rightarrow BTO:n_{H_2{O}_2}=\mathrm{0,03}\Rightarrow n_{H_2}=\mathrm{0,06}\Rightarrow m_X=\mathrm{9,88.}\\ \Rightarrow \left\{\begin{array}{l}{n}_{axit}+2n_{este}=n_{COO}=\mathrm{0,1}\\ n_{axit}+n_{este}=n_{H_2}=\mathrm{0,06}\end{array}\right.\Rightarrow \left\{\begin{array}{l}{n}_{este}=\mathrm{0,04}\\ n_{axit}=\mathrm{0,02}\end{array}\right.\Rightarrow X\stackrel{NaOH}{\to }\left\{\begin{array}{l}{n}_{H_{2}O}=n_{axit}=\mathrm{0,02}\\ n_{C_3{H}_6{\left(OH\right)}_2}=n_{C_3{H}_6{\left(OH\right)}_2/X}+n_{este}=\mathrm{0,07}\end{array}\right.\\ \Rightarrow m_{muoái}=\underset{m_X}{\underbrace{\mathrm{9,88}}}+\underset{m_{KOH}}{\underbrace{\mathrm{0,1.56}}}-\underset{m_{H_{2}O}}{\underbrace{\mathrm{0,02.18}}}-\underset{m_{C_3{H}_6{\left(OH\right)}_3}}{\underbrace{\mathrm{0,07.76}}}=\mathrm{9,8}gam.\end{array}$