Một hợp chất hữu cơ X có công

Chọn đáp án C

Giải thích:

$\begin{array}{l}+Theogiathiet:\\ \left\{\begin{array}{l}{O}_X=4\\ n_X:n_{NaOH}=1:3\end{array}\right.\Rightarrow Xcodang:-COO{C}_6{H}_{4}COO-(*)\\ X(C_X=10)\stackrel{NaOH}{\to }\left\{\begin{array}{l}{C}_n{H}_{2n+1}CHO\\ RCOONa(M<100)\end{array}\right.(**)\\ +Tu(*)va(**),suyra:\left\{\begin{array}{l}n=1;RlaH\\ XlaHCOO{C}_6{H}_{4}COOCH=C{H}_2\end{array}\right.\\ +\left\{\begin{array}{l}\underset{1mol}{\underbrace{X}}+\underset{3mol}{\underbrace{3NaOH}}\stackrel{}{\to }\underset{1mol}{\underbrace{HCOONa}}+NaO{C}_6{H}_{4}COONa+\underset{1mol}{\underbrace{C{H}_{3}CHO}}\\ n_{Ag}=2n_{HCOONa}+2n_{C{H}_{3}CHO}=4\Rightarrow m_{Ag}=432gam.\end{array}\right.\end{array}$