Cho 18 gam hỗn hợp X gồm R2CO3 và

Chọn đáp án A

Giải thích:$\begin{array}{l}+\left\{\begin{array}{l}{n}_{R_{2}C{O}_3}=n_{NaHC{O}_3}=\frac{n_{C{O}_2}}{2}=\mathrm{0,1}\\ \mathrm{0,1.}(2R+60)+\mathrm{0,1.84}=18\end{array}\right.\Rightarrow \left\{\begin{array}{l}R=18\left(N{H}_4\right)\\ R_{2}C{O}_3:{\left(N{H}_4\right)}_{2}C{O}_3\end{array}\right.\\ +\left\{\begin{array}{l}\hspace{0.17em}{\left(N{H}_4\right)}_{2}C{O}_3:\mathrm{0,05}mol\\ NaHC{O}_3:\mathrm{0,05}mol\end{array}\right\}\stackrel{t^o}{\to }\boxed{\underset{\mathrm{0,025}mol\iff \mathrm{2,65}gam}{\underbrace{N{a}_{2}C{O}_{3ran}}}}+\left\{\begin{array}{l}{H}_{2}O,C{O}_2\\ N{H}_3\end{array}\right\}\end{array}$