Đốt cháy hoàn toàn m gam hỗn hợp X chứa hỗn hợp các triglixerit tạo bởi từ cả 3

* Hướng dẫn giải

$$\begin{gathered} +\left\{\begin{array}{l}(\underset{6}{\underbrace{k}}-1)\underset{?}{\underbrace{n_{Xtrongmgam}}}=\underset{\mathrm{0,55}}{\underbrace{n_{C{O}_2}}}-\underset{\mathrm{0,5}}{\underbrace{n_{H_{2}O}}}\\ m_{Xtrongmgam}=856n_{Xtrongmgam}\end{array}\right.\Rightarrow \left\{\begin{array}{l}{n}_{Xtrongmgam}=\mathrm{0,01}\\ m_{Xtrongmgam}=\mathrm{8,56}\end{array}\right. \\ +\left\{\begin{array}{l}\underset{\mathrm{0,06}}{\underbrace{n_{KOH}}}=3\underset{\mathrm{0,02}}{\underbrace{n_{C_3{H}_5{\left(OH\right)}_3}}}=3\underset{\mathrm{0,02}}{\underbrace{n_{Xtrong2mgam}}}\\ \underset{\mathrm{8,56.2}}{\underbrace{m_{Xtrong2mgam}}}+\underset{\mathrm{0,06.56}}{\underbrace{m_{KOH}}}=\underset{?}{\underbrace{m_{xàphòng}}}+\underset{\mathrm{0,02.92}}{\underbrace{m_{C_3{H}_5{\left(OH\right)}_3}}}\end{array}\right.\Rightarrow m_{xàphòng}=\boxed{\mathrm{18,64}gam} \end{gathered}$$