Đạo hàm của hàm số y=(3^x-1)/(5^x) là y'=(3/5)^x.ln 3/5 +(1/5)^x.ln5

A. $y\text{'}={\left(\frac{3}{5}\right)}^x\ln \frac{3}{5}+{\left(\frac{1}{5}\right)}^x\ln 5.$

B. $y\text{'}=x{\left(\frac{3}{5}\right)}^{x-1}-x{\left(\frac{1}{5}\right)}^{x-1}.$

C. $y\text{'}={\left(\frac{3}{5}\right)}^x\ln \frac{3}{5}-{\left(\frac{1}{5}\right)}^x\ln 5.$

D. $y\text{'}=x{\left(\frac{3}{5}\right)}^{x-1}+x{\left(\frac{1}{5}\right)}^{x-1}.$