Nếu (căn3-căn2)^x>căn3+ căn2 thì

Đáp án D

Ta có  $(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})=1\iff \sqrt{3}+\sqrt{2}=\frac{1}{\sqrt{3}-\sqrt{2}}={(\sqrt{3}-\sqrt{2})}^{-1}.$

Nên  ${(\sqrt{3}-\sqrt{2})}^x>\sqrt{3}+\sqrt{2}\iff {(\sqrt{3}-\sqrt{2})}^x>{(\sqrt{3}-\sqrt{2})}^{-1}\iff x<-1$

(vì $0<\sqrt{3}-\sqrt{2}<1$ )