Hỗn hợp X gồm hai chất hữu cơ no, mạch hở (đều chứa C, H, O),

* Hướng dẫn giải

Đáp án A

$\begin{array}{l} \\ + \left\{\begin{array}{l}-C\mathrm{OO}H:x mol\\ -CHO: y mol\end{array}\right.\underset{ }{\to }\left\{\begin{array}{l}Ag:2y mol\\ \underset{x+y}{\underbrace{-C\mathrm{OO}N{H}_4 \stackrel{NaOH}{\to }}}\underset{0,02 mol}{\underbrace{N{H}_3}}\end{array}\right.\\ \\ + \left\{\begin{array}{l}2y=0,0375\\ x+y=0,02\end{array}\right.\Rightarrow \left\{\begin{array}{l}y=0,01875\\ x=1,25.{10}^{-3}\end{array}\right.\\ + m_X=m_{muóai}=1,86-1,25.{10}^{-3}(62-45)-0,01875(62-29)=1,22 gam\end{array}$