Sục 3,36 lít khí CO2 (đktc) vào 200 ml dung dịch NaOH 1M

* Hướng dẫn giải

Đáp án B

$\begin{array}{l}+ \left\{\begin{array}{l}\underset{0,15 mol}{\underbrace{C{O}_2}}+\underset{0,2 mol}{\underbrace{NaOH}}\stackrel{quy đổi}{\to }\underset{0,15 mol}{\underbrace{H_{2}C{O}_3}}+\underset{0,2 mol}{\underbrace{NaOH}}\stackrel{ }{\to } muối+\underset{0,2 mol}{\underbrace{HOH}}\\ BTKL: m_{muối}=\underset{0,15.62}{\underbrace{m_{H_{2}C{O}_3}}}+\underset{0,2.40}{\underbrace{m_{NaOH}}}-\underset{0,2.18}{\underbrace{m_{H_{2}O}}}=13,7 gam\end{array}\right.\\ \bullet PS: n_{H^{+}/H_{2}C{O}_3}>n_{O{H}^{-}}\Rightarrow n_{HOH}=n_{O{H}^{-}}.\end{array}$