Đốt cháy hoàn toàn 0,33 mol hỗn hợp X gồm metyl propiolat, metyl axetat

* Hướng dẫn giải

$\left\{\begin{array}{l}{C}_4{H}_8{O}_2: x mol\\ C_3{H}_6{O}_2: y mol\\ C_n{H}_{2n+2-2k}: z mol\end{array}\right.$

$\left\{\begin{array}{l}\begin{array}{c}\begin{array}{c}{n}_X=x+y+z=0,33\\ BT\left(H\right) \Rightarrow n_{H_{2}O}=4x+3y+(n+1-k)z=0,8\end{array}\end{array}\\ BT(C, O): 2x+2y+2.1,27=\underset{n_{C{O}_2}}{\underbrace{2(4x+3y+nz)+0,8}}\end{array}\right.\iff \left\{\begin{array}{l}x+y+z=0,33\\ 4x+3y+nz+z-kz=0,8\\ 6x+4y+2nz=1,74 \end{array}\right.$

$\iff \left\{\begin{array}{l}x+y+z=0,33\\ kz-(x+y+z)=0,07\end{array}\right.\Rightarrow n_{B{r}_2}=n_{{\pi }_{(C=C)}}=kz=0,4 mol$

Chọn đáp án B.