Phân tích thành nhân tử:
a. x4 + 2x3 + x2
b. x3 – x + 3x2y + 3xy2 + y3 – y
c. 5x2 – 10xy + 5y2 – 20z2
a. x4 + 2x3 + x2 = x2(x2 + 2x + 1) = x2(x + 1)2
b. x3 – x + 3x2y + 3xy2 + y3 – y
= (x3 + 3x2y + 3xy2 + y3) – (x + y) = (x + y)3 – (x + y)
= (x + y)[(x + y)2 – 1] = (x + y)(x + y + 1)(x + y - 1)
c. 5x2 – 10xy + 5y2 – 20z2 = 5(x2 – 2xy + y2 – 4z2)
= 5[(x2 – 2xy + y2) – 4z2] = 5[(x – y)2 – (2z)2]
= 5(x – y + 2z)(x – y – 2z)
-- Mod Toán 8
Copyright © 2021 HOCTAP247