Nếu \(\sin \alpha + \cos \alpha = \frac{1}{2}\) thì \(\sin 2\alpha \) bằng:
(A) \(\frac{3}{8}\)
(B) \(-\frac{3}{4}\)
(C) \(\frac{1}{{\sqrt 2 }}\)
(D) \(\frac{3}{4}\)
Ta có:
\(\begin{array}{l}
\sin \alpha + \cos \alpha = \frac{1}{2}\\
\Rightarrow 1 + 2\sin \alpha \cos \alpha = \frac{1}{4}\\
\Rightarrow \sin 2\alpha = - \frac{3}{4}
\end{array}\)
Chọn (B)
-- Mod Toán 10
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