\(\cos \frac{\pi }{{12}}\cos \frac{{7\pi }}{{12}}\) bằng
(A) \(\frac{{\sqrt 3 }}{2}\)
(B) \(\frac{{\sqrt 3 }}{4}\)
(C) \(\frac{1}{2}\)
(D) \(-\frac{1}{4}\)
Ta có:
\(\begin{array}{l}
\cos \frac{\pi }{{12}}\cos \frac{{7\pi }}{{12}}\\
= \frac{1}{2}\left( {\cos \frac{{2\pi }}{3} + \cos \frac{\pi }{2}} \right) = - \frac{1}{4}
\end{array}\)
Chọn (D)
-- Mod Toán 10
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