Với mọi \(\alpha\), \(\sin \left( {\frac{{3\pi }}{2} + \alpha } \right)\) bằng:
(A) sin α
(B) - sin α
(C) - cos α
(D) cos α
Ta có:
\(\begin{array}{l}
\sin \left( {\frac{{3\pi }}{2} + \alpha } \right) = \sin \left( {\pi + \frac{\pi }{2} + \alpha } \right)\\
= - \sin \left( {\frac{\pi }{2} + \alpha } \right) = - \cos \alpha
\end{array}\)
Chọn (C)
-- Mod Toán 10
Copyright © 2021 HOCTAP247