Cho góc nhọn α
a) Chứng minh rằng: \(\frac{{1 - tg\alpha }}{{1 + tg\alpha }} = \frac{{\cos \alpha - \sin \alpha }}{{\cos \alpha + \sin \alpha }}\)
b) Cho \(tg\alpha = \frac{1}{3}\). Chứng minh \(\frac{{\cos \alpha - \sin \alpha }}{{\cos \alpha + \sin \alpha }}\)
\(\frac{{1 - tg\alpha }}{{1 + tg\alpha }} = \frac{{1 - \frac{{\sin \alpha }}{{\cos \alpha }}}}{{1 + \frac{{\sin \alpha }}{{\cos \alpha }}}} = \frac{{\cos \alpha - \sin \alpha }}{{\cos \alpha + \sin \alpha }}\)
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