Tính
a) \(\frac{{ - 5}}{{13}}.26\)
b) \({\left( {\frac{{ - 2}}{7}} \right)^2}\)
c) \(\left( {2 - \frac{1}{2}} \right).\left( {\frac{{ - 3}}{4} + \frac{1}{2}} \right)\)
Câu a
\(\begin{array}{l}
\frac{{ - 5}}{{13}}.26 = \frac{{ - 5.26}}{{13}}\\
= \frac{{ - 5.2}}{1} = - 10
\end{array}\)
Câu b
\(\begin{array}{l}
{\left( {\frac{{ - 2}}{7}} \right)^2} = \frac{{ - 2}}{7}.\frac{{ - 2}}{7}\\
= \frac{{ - 2.\left( { - 2} \right)}}{{7.7}} = \frac{4}{{49}}
\end{array}\)
Câu c
\(\begin{array}{l}
\left( {2 - \frac{1}{2}} \right).\left( {\frac{{ - 3}}{4} + \frac{1}{2}} \right)\\
= \left( {\frac{4}{2} - \frac{1}{2}} \right).\left( {\frac{{ - 3}}{4} + \frac{2}{4}} \right)\\
= \frac{3}{2}.\frac{{ - 1}}{4} = \frac{{3.\left( { - 1} \right)}}{{2.4}} = \frac{{ - 3}}{8}
\end{array}\)
-- Mod Toán 6
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