Tìm x, biết:
a) \(x - \frac{3}{4}=\frac{1}{2}\) ;
b) \(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\) ;
Câu a:
\(x= \frac{1}{2}+\frac{3}{4}=\frac{5}{4}\) ;
Câu b:
\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\) hay \(\frac{5}{6}-x=\frac{7-4}{12}\) hay \(\frac{5}{6}-x=\frac{3}{12}\).
Suy ra \(x=\frac{-5}{6}-\frac{3}{12}=\frac{-10+3}{12}=\frac{-13}{12}.\)
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