Tính các thương sau rồi sắp xếp chúng theo thứ tự tăng dần:
\(\frac{3}{2}:\frac{9}{4};\frac{{48}}{{55}}:\frac{{12}}{{11}};\frac{7}{{10}}:\frac{7}{5};\frac{6}{7}:\frac{8}{7}\)
\(\begin{array}{l}
\frac{3}{2}:\frac{9}{4} = \frac{3}{2}.\frac{4}{9} = \frac{{12}}{{18}} = \frac{2}{3}\\
\frac{{48}}{{55}}:\frac{{12}}{{11}} = \frac{{48}}{{55}}.\frac{{11}}{{12}}\\
= \frac{4}{5}.1 = \frac{4}{5}\\
\frac{7}{{10}}:\frac{7}{5} = \frac{7}{{10}}.\frac{5}{7} = \frac{5}{{10}} = \frac{1}{2}\\
\frac{6}{7}:\frac{8}{7} = \frac{6}{7}.\frac{7}{8} = \frac{6}{8} = \frac{3}{4}
\end{array}\)
Ta có:
\(\begin{array}{l}
\frac{2}{3} = \frac{{40}}{{60}};\frac{4}{5} = \frac{{48}}{{60}}\\
\frac{1}{2} = \frac{{30}}{{60}};\frac{3}{4} = \frac{{45}}{{60}}
\end{array}\)
Vì \(\frac{{30}}{{60}} < \frac{{40}}{{60}} < \frac{{45}}{{60}} < \frac{{48}}{{60}}\) nên \(\frac{1}{2} < \frac{2}{3} < \frac{3}{4} < \frac{4}{5}\)
Vậy theo thứ tự tăng dần lần lượt là \(\frac{1}{2} ; \frac{2}{3} ; \frac{3}{4} ; \frac{4}{5}\)
-- Mod Toán 6
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