Tìm x, biết \({(\sqrt 3 - \sqrt 2 )^x} = \sqrt 3 + \sqrt 2 \)
A.
B.
C. \(x = \frac{1}{2}\)
D.
\(\begin{array}{l}
{(\sqrt 3 - \sqrt 2 )^x} = \sqrt 3 + \sqrt 2 \Rightarrow {(\sqrt 3 - \sqrt 2 )^x} = \frac{{(\sqrt 3 + \sqrt 2 )(\sqrt 3 - \sqrt 2 )}}{{\sqrt 3 - \sqrt 2 }}\\
\Rightarrow {(\sqrt 3 - \sqrt 2 )^x} = \frac{1}{{\sqrt 3 - \sqrt 2 }} \Rightarrow x = - 1
\end{array}\)
Chọn D.
-- Mod Toán 12
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