Tìm x biết
a) \({\log _x}27 = 3\)
b) \({\log _x}\frac{1}{7} = - 1\)
c) \({\log _x}\sqrt 5 = - 4\)
a) \({\log _x}27 = 3 \Leftrightarrow {x^3} = 27 = {3^3} \Leftrightarrow x = 3\)
b)
\(\begin{array}{l}
{\log _x}\frac{1}{7} = - 1\\
\Leftrightarrow {x^{ - 1}} = \frac{1}{7} = {7^{ - 1}} \Leftrightarrow x = 7
\end{array}\)
c)
\(\begin{array}{l}
{\log _x}\sqrt 5 = - 4 \Leftrightarrow {x^{ - 4}} = \sqrt 5 \\
\Leftrightarrow x = {\left( {\sqrt 5 } \right)^{ - \frac{1}{4}}} = {5^{ - \frac{1}{8}}}
\end{array}\)
-- Mod Toán 12
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