Giá trị của \(\int \limits_{ - 1}^0 {x^2}{\left( {x + 1} \right)^3}dx\) là:
(A) \( - \frac{7}{{10}}\)
(B) \( - \frac{6}{{10}}\)
(C) \(\frac{2}{{15}}\)
(D) \(\frac{1}{{60}}\)
\(\begin{array}{l}
\int\limits_{ - 1}^0 {{x^2}} {\left( {x + 1} \right)^3}dx\\
= \int\limits_{ - 1}^0 {{x^2}} \left( {{x^3} + 3{x^2} + 3x + 1} \right)dx\\
= \int\limits_{ - 1}^0 {\left( {{x^5} + 3{x^4} + 3{x^3} + {x^2}} \right)} dx\\
= \left. {\left( {\frac{{{x^6}}}{6} + \frac{{3{x^5}}}{5} + \frac{{3{x^4}}}{4} + \frac{{{x^3}}}{3}} \right)} \right|_{ - 1}^0 = \frac{1}{{60}}
\end{array}\)
Chọn (D).
-- Mod Toán 12
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