Tính \(\int 2^{\sqrt{x}}.\frac{ln2}{\sqrt{x}}dx\), kết quả sai là:
(A) \(2^{\sqrt{x}+1}+C\)
(B) \(2(2^{\sqrt{x}}-1)+C\)
(C) \(2(2^{\sqrt{x}}+1)+C\)
(D) \(2^{\sqrt{x}}+C\)
Ta có:
\(\int 2^{\sqrt{x}}.\frac{ln2}{\sqrt{x}}dx=2\int 2^{\sqrt{x}}.ln2.d(\sqrt{x})\)
\(=2.2^\sqrt{x}+C.\)
Nên chọn phương án (A).
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