Tính
A. 2 | B. |
C. \(\frac{1}{2}\) | D. 4 |
\(\begin{array}{l}
h\prime \left( x \right) = \sqrt {4 - {x^2}} - x.\frac{{ - 2x}}{{2\sqrt {4 - {x^2}} }}\\
= \frac{{2\left( {4 - {x^2}} \right) + 2{x^2}}}{{\left( {4 - {x^2}} \right)\sqrt {4 - {x^2}} }} = \frac{8}{{\left( {4 - {x^2}} \right)\sqrt {4 - {x^2}} }}\\
\Rightarrow f\prime \left( 0 \right) = \frac{8}{{4.4}} = \frac{1}{2}
\end{array}\)
Đáp án là C
-- Mod Toán 11
Copyright © 2021 HOCTAP247