Cho hàm số \(f(x) = \frac{{2{x^4} + 3}}{{{x^2}}}\). Khi đó
(A) \(\int \nolimits^ f(x)dx = \frac{{2{x^3}}}{3} - \frac{3}{x} + C\)
(B) \(\int \nolimits^ f(x)dx = \frac{{2{x^3}}}{3} + \frac{3}{x} + C\)
(C) \(\int \nolimits^ f(x)dx = 2{x^3} - \frac{3}{x} + C\)
(D) \(\int \nolimits^ f(x)dx = \frac{{2{x^3}}}{3} + \frac{3}{{2x}} + C\)
Ta có:
\(\int \nolimits^ f(x)dx = \int \nolimits^ (2{x^2} + \frac{3}{{{x^2}}})dx = \frac{{2{x^3}}}{3} - \frac{3}{x} + C\)
Chọn (A).
-- Mod Toán 12
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